CompTIA Network+ mcq questions with answer – Set 5

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• Total Number Of Questions : 10
• Passing Marks : 7
• Each Question Carry 1 Mark, No Negative Marking.
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#1. What is the binary representation of the decimal number 117?

10110101

10110101

01110101

01110101

10110110

10110110

01101001

01101001

#2. The binary number 10110100 has what decimal equivalent?

114

114

190

190

172

172

180

180

#3. What is the class of IP address 10.1.2.3/24?

Class A

Class A

Class B

Class B

Class C

Class C

Class D

Class D

#4. Which of the following statements are true regarding VLANs? (Choose two.)

Select all that apply:

A VLAN is a single Layer 2 broadcast domain.

A VLAN is a single Layer 2 broadcast domain.

For traffic to pass between two VLANs, that traffic must be routed by a Layer 3 device.

For traffic to pass between two VLANs, that traffic must be routed by a Layer 3 device.

Because of a switch’s MAC address table, traffic does not need to be routed in order to pass between two VLANs.

Because of a switch’s MAC address table, traffic does not need to be routed in order to pass between two VLANs.

A VLAN is a single collision domain.

A VLAN is a single collision domain.

#5. Which of the following are dynamic approaches to assigning routable IP addresses to networked devices? (Choose two.)

Select all that apply:

BOOTP

BOOTP

APIPA

APIPA

Zeroconf

Zeroconf

DHCP

DHCP

#6. How many assignable IP addresses exist in the 172.16.1.10/27 network?

30

30

32

32

14

14

64

64

#7. What is the prefix notation for a subnet mask of 255.255.255.240?

/20

/20

/24

/24

/28

/28

/29

/29

#8. Your company has been assigned the 192.168.30.0/24 network for use at one of its sites. You need to use a subnet mask that will accommodate seven subnets while simultaneously accommodating the maximum number of hosts per subnet. What subnet mask should you use?

/24

/24

/26

/26

/27

/27

/28

/28

#9. A client with an IP address of 172.16.18.5/18 belongs to what network?

172.16.0.0/18

172.16.0.0/18

172.16.64.0/18

172.16.64.0/18

172.16.96.0/18

172.16.96.0/18

172.16.128.0/18

172.16.128.0/18

#10. How can the following IPv6 address be condensed? 2009:0123:4040:0000:0000:000:000A:100B

2009::123:404:A:100B

2009::123:404:A:100B

2009::123:404:A:1B

2009::123:404:A:1B

2009:123:4040::A:100B

2009:123:4040::A:100B

2009:0123:4040::0::000A:100B

2009:0123:4040::0::000A:100B

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